2048. 下一个更大的数值平衡数

src/main.rs

@@ -1,29 +1,15 @@
-use std::cmp::{max, min};
 mod arr;
 struct Solution {}
 
 impl Solution {
-    pub fn max_frequency(nums: Vec<i32>, k: i32, num_operations: i32) -> i32 {
-        let mut ans = 0;
-        let mut arr = vec![0; 1_000_00 + 10];
-        let mut arr2 = vec![0; 1_000_00 + 10];
-        for &num in nums.iter() {
-            let l = max(num - k, 0);
-            let r = min(1_000_00 + 1, num + k);
-            arr[l as usize] += 1;
-            arr[r as usize + 1] -= 1;
-            arr2[num as usize] += 1;
-        }
-        let mut base = 0;
-        for i in 0..arr.len() {
-            base += arr[i];
-            let local_ans = min(arr2[i] + num_operations, base);
-            ans = max(ans, local_ans);
-        }
-        ans
+    pub fn next_beautiful_number(n: i32) -> i32 {
+        let arr = vec![ 0,1,22,122,212,221,333,1333,3133,3313,3331,4444,14444,22333,23233,23323,23332,32233,32323,32332,33223,33232,33322,41444,44144,44414,44441,55555,122333,123233,123323,123332,132233,132323,132332,133223,133232,133322,155555,212333,213233,213323,213332,221333,223133,223313,223331,224444,231233,231323,231332,232133,232313,232331,233123,233132,233213,233231,233312,233321,242444,244244,244424,244442,312233,312323,312332,313223,313232,313322,321233,321323,321332,322133,322313,322331,323123,323132,323213,323231,323312,323321,331223,331232,331322,332123,332132,332213,332231,332312,332321,333122,333212,333221,422444,424244,424424,424442,442244,442424,442442,444224,444242,444422,515555,551555,555155,555515,555551,666666,1224444 ];
+        let point = arr.partition_point(|v| v <= &n);
+        arr[point]
+
     }
 }
 
 fn main() {
-    println!("{:?}", Solution::max_frequency(vec![1, 1, 1, 4, 5], 1, 2));
+    println!("{:?}", Solution::next_beautiful_number(1333));
 }