757. 设置交集大小至少为2

src/main.rs

@@ -1,15 +1,15 @@
 mod arr;
 struct Solution;
 impl Solution {
-    pub fn find_minimum_time(tasks: Vec<Vec<i32>>) -> i32 {
-        let mut tasks = tasks;
+    pub fn intersection_size_two(intervals: Vec<Vec<i32>>) -> i32 {
+        let mut tasks = intervals;
         tasks.sort_by_key(|task| task[1]);
         let mut stack:Vec<Vec<i32>> = Vec::new();
         stack.push(vec![-2,-2,0]);
         for task in tasks.iter() {
             let start = task[0];
             let end = task[1];
-            let mut d = task[2];
+            let mut d = 2;
             let pos = stack.partition_point(|x| x[0] < start) - 1;
             d -= stack[stack.len() - 1][2] - stack[pos][2];
             if start <= stack[pos][1] {
@@ -27,13 +27,8 @@ impl Solution {
         stack[stack.len() - 1][2]
     }
 }
-/*
-思路来自：
-只是一定程度上理解了思路 但是没有学会这个思路
-作者：灵茶山艾府
-链接：https://leetcode.cn/problems/minimum-time-to-complete-all-tasks/solutions/2163130/tan-xin-pythonjavacgo-by-endlesscheng-w3k3/
-*/
+
 fn main() {
-    let result = Solution::find_minimum_time(arr::make_matrix("[[1,3,2],[2,5,3],[5,6,2]]"));
+    let result = Solution::intersection_size_two(arr::make_matrix("[[1,3],[3,7],[8,9]]"));
     println!("{:?}", result);
 }