1356. 根据数字二进制下 1 的数目排序

src/main.rs

@@ -1,36 +1,26 @@
+use std::cmp::Ordering;
+
 struct Solution;
 mod arr;
 
 impl Solution {
-    pub fn sp(s : &str)-> String{
+    pub fn sort_by_bits(arr: Vec<i32>) -> Vec<i32> {
-        if s.len() <= 2 {
+        let mut arr= arr.iter().map(|&x| ->(i32,i32){
-            return s.to_string();
+            (x,x.count_ones() as i32)
+        }).collect::<Vec<(i32,i32)>>();
+        arr.sort_unstable_by(|a,b|-> Ordering {
+            let res = a.1.cmp(&b.1);
+            match res {
+                Ordering::Equal => a.0.cmp(&b.0),
+                _ => res,
             }
-        let mut left = 0;
+        });
-        let mut cnt = 0;
+        arr.iter().map(|&(x,_)| x).collect()
-        let sb = s.as_bytes();
-        let mut arr = Vec::new();
-        for i in 0..s.len() {
-            if sb[i] == b'1' {
-                cnt += 1;
-            }else {
-                cnt -= 1;
-            }
-            if cnt == 0 {
-                arr.push(format!("1{}0",Self::sp(&s[left + 1 .. i])));
-                left = i + 1;
-            }
-        }
-        arr.sort_unstable_by(|a,b| b.cmp(a));
-        arr.join("")
-    }
-    pub fn make_largest_special(s: String) -> String {
-        Self::sp(s.as_str())
     }
 }
 fn main() {
-    let result = Solution::make_largest_special(
+    let result = Solution::sort_by_bits(
-         "101101101010101010001010101010110011011010001100".to_string(),
+         vec![0,1,2,3,4,5,6,7,8]
     );
     println!("{:?}", result);
 }